a) \(-\left(x+2\right)-\left(x+3\right)=x\)
\(\Leftrightarrow-\left(x+2\right)-\left(x+3\right)-x=0\)
\(\Leftrightarrow-x-2-x-3-x=0\)
\(\Leftrightarrow-3x-5=0\)
\(\Leftrightarrow-3x=5\)
\(\Leftrightarrow x=\dfrac{-5}{3}\)
Vậy \(x=\dfrac{-5}{3}\)
b) \(-\left(x+2\right)+x+3=x\)
\(\Leftrightarrow-\left(x+2\right)+x+3-x=0\)
\(\Leftrightarrow-x-2+x+3-x=0\)
\(\Leftrightarrow-x+1=0\)
\(\Leftrightarrow-x=-1\)
\(\Leftrightarrow x=1\)
Vậy \(x=1\)
c) \(x+2+x+3=x\)
\(\Leftrightarrow x+2+x+3-x=0\)
\(\Leftrightarrow x+5=0\)
\(\Leftrightarrow x=-5\)
Vậy \(x=-5\)
-(x+2)-(x+3)=x
=>-x-2-x-3-x=0
=>-x3-(2+3)=0
=>-3x-5=0
=>-3x=5
=>x=5:(-3)
=>x=-5/3
-(x+2)+x+3=x
=>-x-2+x+3-x=0
=>-x+x-x-2+3=0
=>-x-2+3=0
=>-x=-1=>x=1
Vậy x=1
x+2+x+3=x
=>2x+2+3-x=0
=>1x=-5
Vậy x=-5
