a: \(\Leftrightarrow x-\left\{\left[-x+x+3\right]-\left(x+3-x+2\right)\right\}=0\)
\(\Leftrightarrow x-\left\{3-5\right\}=0\)
=>x+2=0
hay x=-2
b: \(\Leftrightarrow x+\left\{x-3-\left[x+3+x+2\right]\right\}=x\)
\(\Leftrightarrow x-3-\left(2x+5\right)=0\)
=>-x-8=0
hay x=-8