Question

tìm số nguyên x , biết rằng : \(\dfrac{x-2}{-16}=\dfrac{-25}{x-2}\)

giúp mik ,làm ơn

Answer 1

\(\dfrac{x-2}{-16}=\dfrac{-25}{x-2}\)

=> x-2 . x-2 = (-16) . (-25)

x-(2.2) = 400

x-4 = 400

x =400 + 4

x = 404

Answer 2

⇒(x-2)*(x-2)=(-16)*(-25)

⇒(x-2)²=400

⇒x-2ϵ(-2;2)

⇒xϵ(0;4)

Answer 3

A, mình nhầm!!!

⇒(x-2)*(x-2)=(-16)(-25)

⇒(x-2)²=400

⇒(x-2)ϵ(-20;20)

⇒xϵ(-18;22)