\(sinx=cotx\)
=>sinx=cos x/sinx
=>\(sin^2x=cosx\)
=>\(1-cos^2x-cosx=0\)
=>\(cos^2x+cosx-1=0\)
\(\Leftrightarrow\left[{}\begin{matrix}cosx=\dfrac{-1+\sqrt{5}}{2}\left(nhận\right)\\cos=\dfrac{-1-\sqrt{5}}{2}\left(loại\right)\end{matrix}\right.\Leftrightarrow x\simeq52^0\)