a ) \(\left(x-1\right)\left(3x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\3x+2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x-\dfrac{2}{3}\end{matrix}\right.\)
Vậy.............
b ) \(-5x+\dfrac{1}{3}=0\Leftrightarrow-5x=-\dfrac{1}{3}\Leftrightarrow x=\dfrac{1}{15}.\)
Vậy.........