Question

Tìm nghiệm của các đa thức

1) x²-x

2) x² - 2x

3) x²- 3x

4) 3x² - 4x

Zúp mk nha !!!! Mai phải nộp r 

Answer 1

!)

=> x(x - 1)=0

=> \(\left[\begin{array}{nghiempt}x=1\\x-1=0\end{array}\right.\)

=>\(\left[\begin{array}{nghiempt}x=0\\x=1\end{array}\right.\)

Vậy đa thức có nghiệm là x=0 ; x=1

Answer 2

1) \(x^2-x=0\)

\(\Leftrightarrow x\left(x-1\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x-1=0\end{array}\right.\) \(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x=1\end{array}\right.\)

b) \(x^2-2x=0\)

\(\Leftrightarrow x\left(x-2\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x-2=0\end{array}\right.\) \(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x=2\end{array}\right.\)

c)\(x^2-3x=0\)

\(\Leftrightarrow x\left(x-3\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x-3=0\end{array}\right.\) \(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x=3\end{array}\right.\)

d)\(3x^2-4x=0\)

\(\Leftrightarrow x\left(3x-4\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\3x-4=0\end{array}\right.\) \(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x=\frac{4}{3}\end{array}\right.\)

Answer 3

2)

=>x(x - 2)=0

=>\(\left[\begin{array}{nghiempt}x=0\\x=2\end{array}\right.\)

Vậy đa thức có nghiệm x=2 ; x=0

Answer 4

3)

=> x(x - 3)=0

=>\(\left[\begin{array}{nghiempt}x=0\\x=3\end{array}\right.\)

Vậy đa thức có nghiệm x=0 ; x=3

Answer 5

4)

=> x(3x - 4)=0

\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\3x-4=0\end{array}\right.\)

=>\(\left[\begin{array}{nghiempt}x=0\\x=\frac{4}{3}\end{array}\right.\)

Vậy đa thức có nghiệm x=0 ; x=4/3