Ta có: \(10x^2+6x-4=0\)
\(\Leftrightarrow10x^2+10x-4x-4=0\)
\(\Leftrightarrow10x\left(x+1\right)-4\left(x+1\right)=0\)
\(\Leftrightarrow\left(10x-4\right)\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}10x-4=0\\x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-1\end{matrix}\right.\)
Vậy...
\(10x^2+6x-4=0\)
\(\Rightarrow10x^2+10x-4x-4=0\)
\(\Rightarrow10x\left(x+1\right)-4\left(x+1\right)=0\)
\(\Rightarrow\left(10x-4\right)\left(x+1\right)=0\)
\(\Rightarrow\left\{{}\begin{matrix}10x-4=0\Rightarrow10x=4\Rightarrow x=\dfrac{2}{5}\\x+1=0\Rightarrow x=-1\end{matrix}\right.\)