Cho : P(2)=0 =>a23+4.22-1=0
=>8a+16-1=0 => 8a=-15 => a=\(\dfrac{-15}{8}\)
Cho : P(2)=0 =>a23+4.22-1=0
=>8a+16-1=0 => 8a=-15 => a=\(\dfrac{-15}{8}\)
giup minh lam bai nay voi ak. Tim nghiem cua da thuc F(x)= x^2+@x+3
tim nghiem cua da thuc h(x) = ( x-1 ) ( x+1)
chung to rang da thuc kho co nghiem x^2 +4x+4
nghiem cua da thuc N(x)= X^2 +x
chung minh da thuc khong co nghiem : x^2-2x+4
P(x) = -3x2+4x-x3+x2+3x-1 Q(x)=3x4-x2+x3-2x-1-2x3 a) thu gon va sx giam dan b) M(x) =P(x)-Q(x) tim nghiem cua da thuc
cho da thuc x^2+x+1 vo nghiem
cm: da thuc M[x]=\(^{2x^4+4x^2+6}\) ko co nghiem
Cho da thuc M ( x ) = \(x^2\) + 1. C/m M ( x ) khong co nghiem
M.n giup minh vs minh sap thi rui