A\(\ge\left|2x-2-2x+2013\right|=\left|2011\right|=2011\)
Vậy Amin=2011\(\Leftrightarrow\left(2x-2\right)\left(2x-2013\right)\ge0\)
\(\Leftrightarrow\left[{}\begin{matrix}x\le1\\x\ge\dfrac{2013}{2}\end{matrix}\right.\)
tap hop cac gia tri nguyen x cua bieu thuc /2x + 2,5/+/2x -3/ dat gia tri lon nhat
tim gia tri nguyen cua x de bieu thuc:x^2+7/x+1 cung nhan gia tri la so nguyen
tim gia tri cua x de cac bieu thuc sau thuc sau:
A=3x+15
B=2x^2-32 co gia tri bang 0
tim cac gia tri cua x de bieu thuc sau co gia tri bang 0:
P(x)=2x-7+(x-14)
Q(x)=x^2-64
tim cac gia tri cua x de bieu thuc sau co gia tri bang 0:
P(x)=2x-7+(x-14)
Q(x)=x^2-64
Cho don thuc A= -xy2 , B=5xy3z, C=5xy2
a, Tim cac so nguyen x de bieu thuc M= \(\dfrac{3}{7-x}\) dat gia tri lon nhat
tim gia tri cua bieu thuc X=2x^5-5y^3+2015 tai x,y thoa man /x-1/=(y+2)^20=0
Tim gia tri nho nhat cua bieu thuc:
a, A= 2|3x - 2 | - 1
b, B= 5|1 - 4x | - 1
c, C = x2+ 3|y-2| - 1
d, D = x + |x|
e, E = | x - 7 | + 6 - x
Tim x de gia tri cua cac bieu thuc sau =0
a. x^3-x^2-4x-4
b. x^3-x^2+2x-2
c. x^3+6x^2+11x+6
