Giải:
Đặt \(A=\left|2x+2\right|+\left|2x-2013\right|\)
\(\Rightarrow A=\left|2x-2\right|+\left|2013-2x\right|\)
Áp dụng BĐT \(\left|a\right|+\left|b\right|\ge\left|a+b\right|\) ta có:
\(\left|2x-2\right|+\left|2013-2x\right|\ge\left|2x+2+2013-2x\right|=2015\)
Vậy \(MIN_A=2015\)