Question

Tìm ĐKXĐ:

\(\sqrt{\dfrac{x}{\left(x-1\right)^2}}\)

Answer 1

ĐK : \(\left\{{}\begin{matrix}\left(x-1\right)^2\ne0\\\dfrac{x}{\left(x-1\right)^2}\ge0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\ne1\\x>0\end{matrix}\right.\)

Answer 2

ĐKXĐ: \(\left\{{}\begin{matrix}x\ge0\\\left(x-1\right)^2>0\left(1\right)\end{matrix}\right.\)

(1) đúng với mọi x \(\ne1\)

Vậy đkxđ là \(\left\{{}\begin{matrix}x\ge0\\x\ne1\end{matrix}\right.\)