Ta có :
\(yt.yz=48.24\)
\(\Rightarrow y^2.zt=48.24\)
Mà \(yt=32\)
\(\Rightarrow y^2.32=48.24\)
\(\Rightarrow y^2=\frac{48.24}{32}=36\)
\(\Rightarrow y=\pm6\)
+ Nếu \(y=6\)
\(\Rightarrow t=48:6=8\)
\(z=24:6=4\)
\(x=12:6=2\)
+ Nếu \(y=-6\)
\(\Rightarrow t=48:\left(-6\right)=-8\)
\(z=24:\left(-6\right)=-4\)
\(x=12:\left(-6\right)=-2\)
Vậy : \(x=-2;y=-6;z=-4;t=-8\) hoặc \(x=2;y=6;z=4;t=8\)
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