\(\dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z-3}{4}\) (1)
Áp dụng dãy tỉ số bằng nhau , ta có:
\(\left(1\right)\Leftrightarrow\dfrac{\left(x-1\right)+\left(y-2\right)-\left(z-3\right)}{2+3-4}\)
\(=\dfrac{x-1+y-2-x+3}{1}\)
\(=x+y-z=50\)
\(\Rightarrow\left\{{}\begin{matrix}x-1=50.2=100\\y-2=50.3=150\\z-3=50.4=200\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=101\\y=152\\z=203\end{matrix}\right.\)