Question

Tìm các số nguyên x,y,z biết:

\(\frac{-4}{8}=\frac{x}{-10}\frac{-7}{y}=\frac{z}{-24}\)

Answer 1

Ta có : \(\frac{-4}{8}=\frac{-1}{2}\)

+) \(\frac{-1}{2}=\frac{x}{-10}\Rightarrow x.2=-1.\left(-10\right)\)

\(\Rightarrow x.2=10\Rightarrow x=10\div2=5\in Z\)

+) \(\frac{-1}{2}=\frac{-7}{y}\Rightarrow-1.y=-7.2\)

\(\Rightarrow-1.y=-14\Rightarrow-y=-14\Rightarrow y=14\in Z\)

+) \(\frac{-1}{2}=\frac{z}{-24}\Rightarrow z.2=-1.\left(-24\right)\)

\(\Rightarrow z.2=24\Rightarrow z=24\div2=12\in Z\)

Vậy x = 5 ; y = 14 ; z = 12