\(4a^2+4ab+b^2+b^2+c^2+1-2bc+2b-2c+c^2-8c+16\le0\)
\(\Leftrightarrow\left(2a+b\right)^2+\left(b-c+1\right)^2+\left(c-4\right)^2\le0\)
\(\Leftrightarrow\left\{{}\begin{matrix}2a+b=0\\b-c+1=0\\c-4=0\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}c=4\\b=3\\a=-\frac{3}{2}\end{matrix}\right.\)