\(\left|x-7\right|^{2015}+\left(y+10\right)^{2016}=0\)
\(\Rightarrow\left|x-7\right|^{2015}=0\) và \(\left(y+10\right)^{2016}=0\)
+) \(\left|x-7\right|^{2015}=0\Rightarrow\left|x-7\right|=0\Rightarrow x-7=0\Rightarrow x=7\)
+) \(\left(y+10\right)^{2016}=0\Rightarrow y+10=0\Rightarrow y=-10\)
Vậy cặp số \(\left(x;y\right)\) là \(\left(7;-10\right)\)