\(\left|15-a\right|+\left(b-18\right)^2\le0\)
Ta có:
\(\left|15-a\right|\ge0\)
\(\left(b-18\right)^2\ge0\)
Trường hợp này xảy ra khi:
\(\left\{\begin{matrix}\left|15-a\right|=0\\\left(b-18\right)^2=0\end{matrix}\right.\Rightarrow\left\{\begin{matrix}a=15\\b=18\end{matrix}\right.\)