Question

tìm a có giá trị nguyên -a⋮a+3

Answer 1

P=\(\dfrac{6n+5}{3n+2}\)

P=6n+5⋮3n+2

P=2(3n+2)+1⋮3n+2

P=1⋮3n+2

=> 3n+2∈Ư(1)={-1;1}

=> 3n∈{-3;-1}

=> n∈{-1;∅}

vậy...

Answer 2

=>-a-3+3 chia hết cho a+3

=>\(a+3\in\left\{1;-1;3;-3\right\}\)

=>\(a\in\left\{-2;-4;0;-6\right\}\)