Ta có:
\(xy=x:y\)
\(\Rightarrow xy:\dfrac{x}{y}=1\Rightarrow y^2=1\)
\(\Rightarrow y=\pm1\)
Ta lại có:
\(x+y=xy\)
\(\Rightarrow\dfrac{x+y}{xy}=1\Rightarrow\dfrac{1}{x}+\dfrac{1}{y}=1\)
Thay \(y=-1\) thì \(\dfrac{1}{x}-1=1\Rightarrow x=\dfrac{1}{2}\)
Thay \(y=1\) thì \(\dfrac{1}{x}+1=1\Rightarrow\dfrac{1}{x}=0\Rightarrow x\in\varnothing\)
Vậy............
Chúc bạn học tốt!!!