\(\sqrt{\dfrac{2+\sqrt{3}}{2-\sqrt{3}}}-\sqrt{\dfrac{2-\sqrt{3}}{2+\sqrt{3}}}=\sqrt{\dfrac{\left(2+\sqrt{3}\right)^2}{4-3}}-\sqrt{\dfrac{\left(2-\sqrt{3}\right)^2}{4-3}}=\sqrt{\left(2+\sqrt{3}\right)^2}-\sqrt{\left(2-\sqrt{3}\right)^2}=2+\sqrt{3}-2+\sqrt{3}=2\sqrt{3}\)