\(=\dfrac{2^{19}\cdot3^9\cdot5+3^{15}\cdot5\cdot2^{18}}{2^{19}\cdot3^9-2^{20}\cdot3^{10}}\)
\(=\dfrac{2^{18}\cdot3^9\cdot5\left(2+3^6\right)}{2^{19}\cdot3^9\left(1-2\cdot3\right)}=\dfrac{1}{2}\cdot\dfrac{5}{-5}\cdot\left(2+3^6\right)\)
\(=\dfrac{-731}{2}\)
thưc hiện phép tính:
H = \(\dfrac{2^{19}.27^3.5-15.\left(-4\right)^9.9^4}{6^9.2^{10}-\left(-12\right)^{10}}\)
Tính giá trị biểu thức :
\(H=\frac{2^{19}.27^3.5-15.\left(-4\right)^9.9^4}{6^9.2^{10}-\left(-12\right)^{10}}\)
Bài 1: Rút gọn:
a) \(\dfrac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
b) \(\dfrac{\left(\dfrac{-1}{2}\right)^3-\left(\dfrac{3}{4}\right)^3.\left(-2\right)^2}{2.\left(-1\right)^5+\left(\dfrac{3}{4}\right)^2-\dfrac{3}{8}}\)
* Giúp mình với... mình đang cần gấp................
Giúp tôi làm bài này được chứ?
1. Tính giá trị của biểu thức: H = \(\frac{2^{19}.27^3.5-15.\left(-4\right)^9.9^4}{6^9.2^{10}-\left(-12\right)^{10}}\)
2. Cho A = \(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...-\frac{1}{2016}+\frac{1}{2017}-\frac{1}{2018}\);
B = \(\frac{1}{1010}+\frac{1}{1011}+...+\frac{1}{2016}+\frac{1}{2017}+\frac{1}{2018}\)
Tính (A2017 \(-\) B2017)2018
Rút gọn biểu thức :\(\dfrac{3^9.2^{19}+15.9^4.2^{18}}{6^9.2^{10}+3^{10}+2^{20}}\)
tìm x biết : \(\left|\left|\dfrac{2}{3}x-4\right|-7\right|=2012\)
Bài 1: Cho: A= 13+23+33+...+103
Tính B= 23+43+63+...+203 theo A
Bài 2: Tính
A= \(\dfrac{2^{12}.3^5-4^6.9^3}{\left(2^2.3\right)^6+\left(8^4.3^5\right)}\) - \(\dfrac{5^{10}.7^3-25^2.49^2}{\left(125.7\right)^3+5^9.14^3}\)
B= \(\dfrac{2^9.27^3+15.4^9.9^4}{6^9.2^0+12^{10}}\)
Giúp mình gấp nha!
Iu các bạn nhìu!
tính" \(\dfrac{\left(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}\right).203\dfrac{1}{25}+46\dfrac{3}{4}}{\left(1\dfrac{3}{7}+\dfrac{10}{3}\right):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\)
tính:
O = \(\dfrac{\left(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}\right).230\dfrac{1}{25}+46\dfrac{3}{4}}{\left(1\dfrac{3}{10}+\dfrac{10}{3}\right):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\)
\(\dfrac{\left(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}\right).230\dfrac{1}{25}+46\dfrac{3}{4}}{\left(1\dfrac{3}{10}+\dfrac{10}{3}\right):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\)
\(\dfrac{\left(1+2+3+...+99+100\right)\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{9}\right)\left(63.1,2-21.3,6\right)}{1-2+3-4+.....+99-100}\)
