a, \(\dfrac{4}{x^2-4}-\dfrac{2x}{x^2-4}=\dfrac{4-2x}{x^2-4}=\dfrac{-2\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=-\dfrac{2}{x+2}\)
\(b,\dfrac{3x+5}{x^2-5x}+\dfrac{x-25}{5x-25}\)
\(=\dfrac{3x+5}{x\left(x-5\right)}+\dfrac{x-25}{5\left(x-5\right)}\)
\(=\dfrac{5\left(3x+5\right)}{5x\left(x-5\right)}+\dfrac{\left(x-25\right)x}{5x\left(x-5\right)}\)
\(=\dfrac{15x+25+x^2-25x}{5x\left(x-5\right)}\)
\(=\dfrac{x^2-10x+25}{5x\left(x-5\right)}\)
\(=\dfrac{\left(x-5\right)^2}{5x\left(x-5\right)}=\dfrac{x-5}{5x}\)
\(c,\left(\dfrac{2}{x-1}-\dfrac{2}{x+1}\right).\dfrac{x^2+2x+1}{4}\)
\(=\left(\dfrac{2\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}-\dfrac{2\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}\right).\dfrac{\left(x+1\right)^2}{4}\)
\(=\dfrac{2x+2-2x+2}{\left(x-1\right)\left(x+1\right)}.\dfrac{\left(x+1\right)^2}{4}\)
\(=\dfrac{4}{\left(x-1\right)\left(x+1\right)}.\dfrac{\left(x+1\right)^2}{4}\)
\(=\dfrac{x+1}{x-1}\)
