Question

Thực hiện dãy tính:
\(4.\left(\dfrac{-1}{3}\right)^3-2.\left(\dfrac{-1}{2}\right)^2+3.\left(\dfrac{1}{2}\right)+1\)
Cảm ơn nha!

Answer 1

Ta có: \(4\cdot\left(-\dfrac{1}{3}\right)^3-2\left(-\dfrac{1}{2}\right)^2+3\cdot\dfrac{1}{2}+1\)

\(=\dfrac{-4}{27}-2\cdot\dfrac{1}{4}+\dfrac{3}{2}+1\)

\(=\dfrac{-4}{27}-\dfrac{1}{2}+\dfrac{3}{2}+1\)

\(=\dfrac{-4}{27}+2\)

\(=\dfrac{50}{27}\)

Answer 2

\(4.\left(\dfrac{-1}{3}\right)^3-2.\left(\dfrac{-1}{2}\right)^2+3.\left(\dfrac{1}{2}\right)+1\) 

\(=4.\dfrac{-1}{27}-2.\dfrac{1}{4}+3.\dfrac{1}{2}+1\) 

\(=\dfrac{-4}{27}-\dfrac{1}{2}+\dfrac{3}{2}+1\) 

\(=\dfrac{50}{27}\)