Question

\(\text{Tìm x, biết:}\)

\(20\text{%}x-x+\dfrac{1}{5}=\dfrac{3}{4}\)

Answer 1

Ta có: \(20\%x-x+\dfrac{1}{5}=\dfrac{3}{4}\)

\(\Leftrightarrow\dfrac{-4}{5}x=\dfrac{3}{4}-\dfrac{1}{5}=\dfrac{15}{20}-\dfrac{4}{20}=\dfrac{11}{20}\)

\(\Leftrightarrow x=\dfrac{11}{20}:\dfrac{-4}{5}=\dfrac{11}{20}\cdot\dfrac{5}{-4}=\dfrac{-55}{80}=\dfrac{-11}{16}\)

Vậy: \(x=-\dfrac{11}{16}\)