Ta có
\(\left|3x-6\right|=x+2\)
\(\Rightarrow\left[\begin{array}{nghiempt}3x-6=x+2\\6-3x=x+2\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}4x=8\\4x=4\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=2\\x=1\end{array}\right.\)
Vậy x=1 ; x=2
\(\left|3.x-6\right|=x+2\)
\(\Rightarrow3.x-6=x+2\) hoặc \(3x-6=-\left(x+2\right)\)
+) \(3.x-6=x+2\)
\(\Rightarrow3.x-x=2+6\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=4\)
+) \(3.x-6=-\left(x+2\right)\)
\(\Rightarrow3.x-6=-x-2\)
\(\Rightarrow3.x-\left(-x\right)=-2+6\)
\(\Rightarrow4.x=4\)
\(\Rightarrow x=1\)
Vậy \(x\in\left\{4;1\right\}\)
\(\left|3x-6\right|=x+2\)
=>\(3x-6=x+2\) hoặc \(3x-6=-\left(x+2\right)\)
\(3x-x=6+2\) \(3x-\left(-x\right)=6+\left(-2\right)\)
\(2x=8\) \(4x=4\)
\(x=8:2\) \(x=4:4\)
\(x=4\) \(x=1\)
Vậy \(x=4\) hoặc \(x=1\)
