Đặt \(A=\dfrac{a^2+a+3}{a+1}\\ \) ta có:
\(A=\dfrac{a^2+a+3}{a+1}=\dfrac{a\left(a+1\right)+3}{a+1}=a+\dfrac{3}{a+1}\)
để A nguyên => \(3⋮a+1\\ \)
\(\Rightarrow3⋮a+1\\ \Rightarrow a+1\inƯ_{\left(3\right)}=\left\{1;-1;3;-3\right\}\)
ta có bảng sau:
| a+1 | 1 | -1 | 3 | -3 |
| a | 0 | -2 | 2 | -4 |
vậy a = {0;-2;2;-4}
tim so nguyen a de : a^2 + 5a +4 / a + 5 la mot so nguyen
so nguyen a de 3/7-3a la so tu nhien a la
cho x, y la cac so nguyen duong sao cho A = x^4 + y^4 / 15 cung la so nguyen duong . cmr : x va y deu chia het cho 3 va 5 , tu do tim gtnn cua A
A=\(\dfrac{\sqrt{x-3}}{2}\) Tim x de A la so nguyen
so cac so nguyen to co 2 chu so la
tim gia tri nguyen cua x de bieu thuc:x^2+7/x+1 cung nhan gia tri la so nguyen
Tim n de bieu thuc sau la so nguyen : P = \(\dfrac{3n+2}{n-1}\)
tap hop cac gia tri nguyen x cua bieu thuc /2x + 2,5/+/2x -3/ dat gia tri lon nhat
Cho don thuc A= -xy2 , B=5xy3z, C=5xy2
a, Tim cac so nguyen x de bieu thuc M= \(\dfrac{3}{7-x}\) dat gia tri lon nhat
