Bài 1: Thu thập số liệu, tần số
Các câu hỏi tương tự
\(\left|x+1\right|+\left|x+2\right|=0\)
1) Tính :
a)(1000-1^3)(1000-2^3)(1000-3^3)....(1000-2^2018)
2)Tìm x , biết :
\(\dfrac{27}{3^x}\)=3
3) Tìm x, y biết :
a)\(x^2\)+\(\left(y-\dfrac{1}{10}\right)^{2018}\)=0
b)\(\left(\dfrac{1}{2}x-5\right)^{20}\)+\(\left(y^2-\dfrac{1}{4}\right)^{10}\)\(\le\)0
1. tim x biet
\(\left|x-3\right|-\left|x+1,5\right|=0\)
Tìm x:
a/dfrac{x-1}{x+5}dfrac{6}{7}
b/dfrac{x^2}{-6}-dfrac{24}{25}
c/dfrac{x+4}{20}dfrac{5}{x+4}
d/2,5:4x0,5:0,2
e/dfrac{1}{5}x:3dfrac{2}{3}:0,25
g/1,25:0,8dfrac{3}{8}:0,2x
f/-3:left(-2dfrac{1}{4}right)dfrac{3}{4}:left(-6xright)
h/3:dfrac{2}{5}x1:0,01
j/2:1dfrac{1}{4}dfrac{1}{2}:2x
l/dfrac{4}{x-1}dfrac{x-1}{9}
Đọc tiếp
Tìm x:
a/\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
b/\(\dfrac{x^2}{-6}=-\dfrac{24}{25}\)
c/\(\dfrac{x+4}{20}=\dfrac{5}{x+4}\)
d/\(2,5:4x=0,5:0,2\)
e/\(\dfrac{1}{5}x:3=\dfrac{2}{3}:0,25\)
g/\(1,25:0,8=\dfrac{3}{8}:0,2x\)
f/\(-3:\left(-2\dfrac{1}{4}\right)=\dfrac{3}{4}:\left(-6x\right)\)
h/\(3:\dfrac{2}{5}x=1:0,01\)
j/\(2:1\dfrac{1}{4}=\dfrac{1}{2}:2x\)
l/\(\dfrac{4}{x-1}=\dfrac{x-1}{9}\)
Bài 1:Thực hiện phép tính
a, 0,5-frac{5}{41}+frac{1}{2}-frac{36}{41}
b,(-frac{1}{3})2.frac{4}{11}+frac{7}{11}.(frac{1}{3})2
c,(-frac{2}{3}+frac{3}{7}):frac{4}{5}+(-frac{1}{3}+frac{4}{7}):frac{4}{5}
d,frac{48^2.8^5.100^9}{12^2.2^{15}.4^2}
e,(-2)3 -sqrt{0,36} - |-2,4|
f,|-frac{3}{4}|.sqrt{frac{16}{9}}+ 3sqrt{49}
Đọc tiếp
Bài 1:Thực hiện phép tính
a, 0,5-\(\frac{5}{41}\)+\(\frac{1}{2}\)-\(\frac{36}{41}\)
b,(-\(\frac{1}{3}\))2.\(\frac{4}{11}\)+\(\frac{7}{11}\).(\(\frac{1}{3}\))2
c,(-\(\frac{2}{3}\)+\(\frac{3}{7}\)):\(\frac{4}{5}\)+(-\(\frac{1}{3}\)+\(\frac{4}{7}\)):\(\frac{4}{5}\)
d,\(\frac{48^2.8^5.100^9}{12^2.2^{15}.4^2}\)
e,(-2)3 -\(\sqrt{0,36}\) - |-2,4|
f,|-\(\frac{3}{4}\)|.\(\sqrt{\frac{16}{9}}\)+ 3\(\sqrt{49}\)
[TEX]frac{a}{c} frac{b}{d}[/TEX]
Rightarrow [TEX]adcb[/TEX]
Rightarrow [TEX]2ad2cb[/TEX]
Rightarrow [TEX]ad-cbcb-ad[/TEX]
Rightarrow[TEX]ab(ad-cb)ab(cb-ad)[/TEX]
Rightarrow[TEX]a^2bd- acb^2 acb^2-a^2bd[/TEX]
Rightarrow[TEX]16a^2b^2-36abcd+24a^2bd-24acb^2 16a^2b^2- 36abcd+24acb^2-24a^2bd[/TEX]
Rightarrow[TEX]( 4a^2 - 6ac)(4b^2 + 6bd) ( 4a^2 +6ac)(4b^2 - 6bd)[/TEX]
C2: [TEX]frac{a}{c} frac{b}{d}[/TEX]Rightarrow[TEX] (frac{a}{b})^2( frac{c}{d})^2 frac{ac}{bd}frac{-12ac}{-12bd} frac{(4a^2-6ac)-...
Đọc tiếp
\( [TEX]\frac{a}{c} = \frac{b}{d}[/TEX] \Rightarrow [TEX]ad=cb[/TEX] \Rightarrow [TEX]2ad=2cb[/TEX] \Rightarrow [TEX]ad-cb=cb-ad[/TEX] \Rightarrow[TEX]ab(ad-cb)=ab(cb-ad)[/TEX] \Rightarrow[TEX]a^2bd- acb^2= acb^2-a^2bd[/TEX] \Rightarrow[TEX]16a^2b^2-36abcd+24a^2bd-24acb^2 = 16a^2b^2- 36abcd+24acb^2-24a^2bd[/TEX] \Rightarrow[TEX]( 4a^2 - 6ac)(4b^2 + 6bd) =( 4a^2 +6ac)(4b^2 - 6bd)[/TEX] C2: [TEX]\frac{a}{c} = \frac{b}{d}[/TEX]\Rightarrow[TEX] (\frac{a}{b})^2=( \frac{c}{d})^2= \frac{ac}{bd}=\frac{-12ac}{-12bd}= \frac{(4a^2-6ac)-(4a^2+6ac)}{(4b^2- 6bd)- (4b^2+6bd)} [/TEX]\)
Cho x/z=z/y. Chứng minh rằng : x^2+z^2/y^2+z^2=x/y
Chứng minh rằng1/6<1/5^2+1/6^2+1/7^2+........+1/100^2<1/4
Câu 24. Trong các điểm sau, điểm nào thuộc đồ thị hàm số y = 3x
A. (- 1; - 2)
B. (- 1; 2)
C. (- 2: - 6)
D. ( - 2; 6)