Question

\(\sqrt{\dfrac{\left(\sqrt{5}-3\right)^2}{48}}\)

Answer 1

`sqrt{(sqrt5-3)^2/48}`

`=|(sqrt5-3)|/sqrt{48}`

Vì `3=sqrt9>sqrt5`

`=>|sqrt5-3|=3-sqrt5`

`=>sqrt{(sqrt5-3)^2/48}`

`=(3-sqrt5)/(sqrt{16.3})`

`=(3-sqrt5)/(4sqrt3)=(3sqrt3-sqrt15)/12`

Answer 2

\(\sqrt{\dfrac{\left(\sqrt{5}-3\right)^2}{48}}=\dfrac{3-\sqrt{5}}{4\sqrt{3}}=\dfrac{-\sqrt{15}+3\sqrt{3}}{12}\)