Giải:
\(\sqrt{\dfrac{0,09}{25}}=\dfrac{-4,7}{5}+x\)
\(\Leftrightarrow\dfrac{0,3}{5}=\dfrac{-4,7}{5}+x\)
\(\Leftrightarrow x=\dfrac{0,3}{5}-\dfrac{-4,7}{5}\)
\(\Leftrightarrow x=\dfrac{0,3}{5}+\dfrac{4,7}{5}\)
\(\Leftrightarrow x=\dfrac{0,3+4,7}{5}\)
\(\Leftrightarrow x=\dfrac{5}{5}=1\)
Vậy \(x=1\).
Chúc bạn học tốt!
Tìm x, biết:
\(x=\dfrac{19}{11}\cdot\dfrac{5}{14}+\dfrac{1}{11}\cdot\dfrac{5}{7}-\sqrt{\dfrac{25}{4}}\cdot\dfrac{2}{11}\)
Tính
a) \(2\sqrt{\dfrac{25}{16}}-3\sqrt{\dfrac{49}{36}}+4\sqrt{\dfrac{81}{64}}\)
b) \(\left(3\sqrt{2}\right)^2-\left(4\sqrt{\dfrac{1}{2}}\right)^2+\dfrac{1}{16}.\left(\sqrt{\dfrac{3}{4}}\right)^2\)
c) \(\dfrac{2}{3}\sqrt{\dfrac{81}{16}}-\dfrac{3}{4}\sqrt{\dfrac{64}{9}}+\dfrac{7}{5}.\sqrt{\dfrac{25}{196}}\)
Thực hiện phép tính \(\left(\dfrac{1}{\sqrt{625}}+\dfrac{1}{5}+1\right)\div\left(\dfrac{1}{25}-\dfrac{1}{\sqrt{25}}-1\right)\)
b, \(\left(\dfrac{4}{5}\right)^x\) - \(\sqrt{\left(\dfrac{2}{5}\right)^4}\) = \(\sqrt{2^3+3^3-19}\) - \(/-3\dfrac{12}{25}/\)
Bài 1 :
a) Tính B = \(\dfrac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.35}-\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.\left(\sqrt{196}\right)^3}\)
b)Tìm x biết : \(\left|x-\dfrac{1}{3}\right|+\dfrac{4}{5}=\left|-3,2+\sqrt{\dfrac{4}{25}}\right|\)
c)Tính \(\left|3x+1\right|>4\)
Tính :
\(\sqrt{\dfrac{1}{9}}\) . \(\sqrt{0,81}\) + \(\sqrt{0,09}\)
1 tính
\(\left(-\dfrac{1}{3}+\dfrac{5}{6}\right)^2-\dfrac{\sqrt{25^2-\sqrt{49^2}}}{\sqrt{36^2+\sqrt{38^2}}}\)
Thực hiện phép tính:
\(A=\dfrac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
\(B=\dfrac{1-\dfrac{1}{\sqrt{49}}+\dfrac{1}{49}-\dfrac{1}{\left(7\sqrt{7}\right)^2}}{\dfrac{\sqrt{64}}{2}-\dfrac{4}{7}+\dfrac{2^2}{7^2}-\dfrac{4}{343}}\)
tinh: C=25.(\(\dfrac{-1}{3}\))\(^3\)+\(\dfrac{1}{5}\)-2.(\(\dfrac{-1}{2}\))\(^2\)-\(\dfrac{1}{2}\)
E=5\(\sqrt{16}\)-4\(\sqrt{9}\)+\(\sqrt{25}\)-0,3\(\sqrt{400}\)
