Bài 1: Căn bậc hai
Các câu hỏi tương tự
\(\sqrt{53-20\sqrt{4-\sqrt{9+4\sqrt{2}}}}\)
1)sqrt{12}-sqrt{27}+sqrt{48}2)(sqrt{24}+sqrt{20}-sqrt{80})div53)2sqrt{27}-sqrt{dfrac{16}{3}}-sqrt{48}-sqrt{8dfrac{1}{3}}4) dfrac{1}{sqrt{5}-sqrt{3}}-dfrac{1}{sqrt{5+sqrt{3}}}
Đọc tiếp
1)\(\sqrt{12}\)\(-\)\(\sqrt{27}\)\(+\)\(\sqrt{48}\)
2)(\(\sqrt{24}+\sqrt{20}-\sqrt{80}\))\(\div\)5
3)2\(\sqrt{27}-\sqrt{\dfrac{16}{3}}\)\(-\)\(\sqrt{48}-\)\(\sqrt{8\dfrac{1}{3}}\)
4) \(\dfrac{1}{\sqrt{5}-\sqrt{3}}\)\(-\)\(\dfrac{1}{\sqrt{5+\sqrt{3}}}\)
\(\sqrt{53-20\sqrt{4+\sqrt{9+4\sqrt{2}}}}\)
Giúp mình với ạ:)) Mình cảm ơn nhiều ạ :))
Tính:
a,\(\sqrt{6-2\sqrt{5}}-\sqrt{20}-1\)
b,\(\sqrt{9}+4\sqrt{5}-\sqrt{9-4\sqrt{5}}\)
c,(\(\sqrt{4-2\sqrt{3}}-1).\frac{1}{2\sqrt{3}-4}\)
(cảm ơn)
\(a,\frac{2}{\sqrt{13}-\sqrt{11}}+\frac{5}{4+\sqrt{ }11}-\sqrt{52}
\)
b,\(\sqrt{6+2\sqrt{5}+\sqrt{9-4\sqrt{5}}-\sqrt{20}}\)
\(\dfrac{1}{3}\sqrt{45}-\sqrt{20}+\sqrt{9+4\sqrt{5}}\)
\(\sqrt{5-2\sqrt{2+\sqrt{9+4\sqrt{2}}}}\sqrt{\sqrt{3-\sqrt{4-\sqrt{2-\sqrt{6-4\sqrt{10-4\sqrt{6}}}}}}}\)
Bài 1: Giải PT
a) \(\sqrt{x^2-1}-x^2+1=0\)
b) \(\sqrt{x^2-4}-x+2=0\)
c) \(\sqrt{x^4-8x^2+16}=2-x\)
d) \(\sqrt{9x^2+6x+1}\sqrt{11-6\sqrt{2}}\)
e) \(\sqrt{4^2-9}=2\sqrt{2x+3}\)
f) \(\sqrt{4x-20}+3\sqrt{\dfrac{x-5}{9}}-\dfrac{1}{3}\sqrt{9x-45}=4\)
thực hiện phép tính
A=\(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
B=\(\left(5+2\sqrt{6}\right)\cdot\left(49-20\sqrt{6}\right)\sqrt{5-2\sqrt{6}}\)