ĐK: \(\forall x\in R\)
\(PT\Leftrightarrow x^3+x+1=7x-3\)
\(\Leftrightarrow x^3-6x+4=0\)
\(\Rightarrow\left[{}\begin{matrix}x=-1-\sqrt{3}\\x=2\end{matrix}\right.\left(tm\right)\)
gpt a/ \(\left(5x+1\right)\sqrt{2x+1}-\left(7x+3\right)\sqrt{x}=1\)
b/ \(2\sqrt{1-x}-\sqrt{1+x}+3\sqrt{1-x^2}=3-x\)
Giải phương trình:
a) \(5x^2-10x=4\left(x-1\right)\sqrt{x^2-2x+2}\)
b) \(\sqrt{2x^2+22x+29}-x-2=2\sqrt{2x+3}\)
c) \(x^3-7x^2+9x+12=\left(x-3\right)\left(x-2+5\sqrt{x-3}\right)\left(\sqrt{x-3}-1\right)\)
\(x^3+7+\sqrt{3-2x}=7x+\sqrt{3x+1}\)
Giải phương trình: \(x^3-7x^2+9x+12=\left(x-3\right)\left(x-2+5\sqrt{x-3}\right)\left(\sqrt{x-3}-1\right)\) ?
Giai pt:
a, \(x^2+\sqrt[3]{x^4-x^2}=2x+1\)
b, \(x+1+\sqrt{x^2-4x+1}=3\sqrt{x}\)
c, \(\sqrt{2x^2+7x+10}+\sqrt{2x^2+x+4}=3\left(x+1\right)\)
d, \(2\left(x^2-3x+2\right)=3\sqrt{x^3+8}\)
Mong moi nguoi giup do, em can gap !!!
Giải các phương trình sau
\(\sqrt{x-8}+\sqrt{3x+7}=\sqrt{7x+3}+3\sqrt{x+2}\)
\(\left(5x+1\right)\sqrt{2x+1}-\left(7x+3\right)\sqrt{x}=1\)
Cmr: \(\dfrac{9x^2+7x+1}{6x+3}< 0,\forall x\le\dfrac{1-\sqrt{5}}{2},x\ge\dfrac{1+\sqrt{5}}{2}\)
\(\begin{cases}4x^3-4x^2-7x=\left(3y^2-6y+4\right)\sqrt{3y^2-6y+7}\\\left(x^3-3x^2\right)\left(\sqrt{x^2+\left(y-1\right)^2}+3\right)+8=\left(x^2+y^2-2y\right)^2-7\left(x^2+y^2-2y\right)\end{cases}\)
