A/đặt A=\(\sqrt{30+12\sqrt{6}}+\sqrt{30-12\sqrt{6}}\)
\(\Leftrightarrow A^2=60+\sqrt{\left(30+12\sqrt{6}\right)\left(30-12\sqrt{6}\right)}\)
=\(60+6=66\)
\(\Leftrightarrow A=\sqrt{66}\)
B/ đặt B=\(\sqrt{4+\sqrt{7}}-\sqrt{4-\sqrt{7}}\)
\(\Leftrightarrow B^2=8-\sqrt{\left(4+\sqrt{7}\right)\left(4-\sqrt{7}\right)}=5\)
\(\Leftrightarrow B=\sqrt{5}\)
\(\Leftrightarrow B-\sqrt{2}=\sqrt{5}-\sqrt{2}\)
hay \(\sqrt{4+\sqrt{7}}-\sqrt{4-\sqrt{7}}\) \(-\sqrt{2}=\sqrt{5}-\sqrt{2}\)