Question

\(\sqrt{2x^2-1}+\sqrt{x^2-3x-2}=\sqrt{2x^2+2x+3}+\sqrt{x^2-x+2}\)

Answer 1

\(\Leftrightarrow\sqrt{2x^2-1}-\sqrt{2x^2+2x+3}+\) \(\sqrt{x^2-3x-2}-\sqrt{x^2-x+2}=0\)

\(\Leftrightarrow\dfrac{2x^2-1-2x^2-2x-3}{...}+\dfrac{x^2-3x-2-x^2+x-2}{...}=0\)

\(\Leftrightarrow\dfrac{-2x-4}{...}+\dfrac{-2x-4}{...}=0\Leftrightarrow\left(x+2\right)\left(...\right)=0\)

<> x=-2

^_^