\(\sqrt{11+6\sqrt{2}}-\sqrt{11-6\sqrt{2}}\)
\(=3+\sqrt{2}-3+\sqrt{2}\)
\(=2\sqrt{2}\)
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Chương I - Căn bậc hai. Căn bậc ba
Các câu hỏi tương tự
\(\sqrt{3-2\sqrt{2}}-\sqrt{11+6\sqrt{2}}\)
\(\sqrt{4-2\sqrt{3}}-\sqrt{7-4\sqrt{3}}+\sqrt{19+8\sqrt{3}}\)
\(\sqrt{6-2\sqrt{5}}+\sqrt{9+4\sqrt{5}}-\sqrt{14-6\sqrt{5}}\)
\(\sqrt{11-4\sqrt{7}}+\sqrt{23-8\sqrt{7}}+\sqrt{\left(-2^6\right)}\)
rút gọn:giải chi tiết hộ mình nha
\(6\sqrt{2}\) + \(\sqrt{6-\sqrt{11}}\)\(-\sqrt{6+\sqrt{11}}\)
thu gon
mik can gap gip mik vs
\(\dfrac{6}{\sqrt{5}+\sqrt{11}}\)-\(\dfrac{11+\sqrt{11}}{\sqrt{11}+1}\)+\(\dfrac{1}{2\sqrt{5}}\)
Rút gọn :
a. \(\sqrt{6+2\sqrt{5}}+\sqrt{6-2\sqrt{5}}\)
b.\(\sqrt{8-2\sqrt{7}}-\sqrt{8+2\sqrt{7}}\)
c.\(\sqrt{11+6\sqrt{2}}-\sqrt{11-6\sqrt{2}}\)
d.\(\sqrt{3+2\sqrt{2}}+\sqrt{6-4\sqrt{2}}\)
Tính giá trị các biểu thức:
A = \(\sqrt{8+2\sqrt{7}}-\sqrt{8-2\sqrt{7}}\)
B = \(\sqrt{11-6\sqrt{2}}+\sqrt{6-4\sqrt{2}}\)
Phân tích
a) \(\sqrt{5-2\sqrt{6}}+\sqrt{5+2\sqrt{6}}\)
b) \(\sqrt{7-2\sqrt{10}}+\sqrt{7+2\sqrt{10}}\)
c) \(\sqrt{11+2\sqrt{8}}+\sqrt{11-2\sqrt{8}}\)
Tính
a) left(dfrac{3}{2}sqrt{6}+2sqrt{dfrac{2}{3}}+4sqrt{dfrac{3}{2}}right)timesleft(2sqrt{dfrac{2}{3}}-sqrt{12}-sqrt{6}right)
b) sqrt{6-2sqrt{5}}-sqrt{6+2sqrt{5}}
c) left(sqrt{11+2sqrt{24}}-sqrt{11-2sqrt{24}}right):2sqrt{3}
d) sqrt{3-sqrt{5}}-sqrt{3+sqrt{5}}
e) sqrt{5+6sqrt{2}}-sqrt{9-6sqrt{2}}-sqrt{21-12sqrt{3}}
f) sqrt{6+2sqrt{5-sqrt{13+sqrt{48}}}}
Đọc tiếp
Tính
a) \(\left(\dfrac{3}{2}\sqrt{6}+2\sqrt{\dfrac{2}{3}}+4\sqrt{\dfrac{3}{2}}\right)\times\left(2\sqrt{\dfrac{2}{3}}-\sqrt{12}-\sqrt{6}\right)\)
b) \(\sqrt{6-2\sqrt{5}}-\sqrt{6+2\sqrt{5}}\)
c) \(\left(\sqrt{11+2\sqrt{24}}-\sqrt{11-2\sqrt{24}}\right):2\sqrt{3}\)
d) \(\sqrt{3-\sqrt{5}}-\sqrt{3+\sqrt{5}}\)
e) \(\sqrt{5+6\sqrt{2}}-\sqrt{9-6\sqrt{2}}-\sqrt{21-12\sqrt{3}}\)
f) \(\sqrt{6+2\sqrt{5-\sqrt{13+\sqrt{48}}}}\)
\(\dfrac{\sqrt{5+\sqrt{3}}+\sqrt{5-\sqrt{3}}}{\sqrt{5+\sqrt{22}}}+\sqrt{11-6\sqrt{2}}\)
\(\sqrt{x+6-4\sqrt{x+2}}+\sqrt{x+11-6\sqrt{x+2}}=1\)