Question

So sánh: \(\sqrt{20152015}+\sqrt{20152017}\) với \(2\sqrt{20152016}\)

Answer 1

Lời giải:

Ta có:

$\sqrt{2015.2015}+\sqrt{2015.2017}=\sqrt{2015}(\sqrt{2015}+\sqrt{2017})$

Mà:

$(\sqrt{2015}+\sqrt{2017})^2=4032+2\sqrt{2015.2017}$

$=4032+2\sqrt{(2016-1)(2016+1)}=4032+2\sqrt{2016^2-1}$

$< 4032+2\sqrt{2016^2}=4.2016$

$\Rightarrow \sqrt{2015}+\sqrt{2017}< 2\sqrt{2016}$

$\Rightarrow \sqrt{2015.2015}+\sqrt{2015.2017}=\sqrt{2015}(\sqrt{2015}+\sqrt{2017})< \sqrt{2015}.2\sqrt{2016}$

Vậy......

Answer 2

Lời giải:

\(\sqrt{20152015}+\sqrt{20152017}-2\sqrt{20152016}=(\sqrt{20152015}-\sqrt{20152016})+(\sqrt{20152017}-\sqrt{20152016})\)

\(=\frac{-1}{\sqrt{20152015}+\sqrt{20152016}}+\frac{1}{\sqrt{20152017}+\sqrt{20152016}}\)

Dễ thấy: $0< \sqrt{20152015}+\sqrt{20152016}<\sqrt{20152017}+\sqrt{20152016}}$

$\Rightarrow \frac{1}{\sqrt{20152015}+\sqrt{20152016}}>\frac{1}{\sqrt{20152017}+\sqrt{20152016}}$

$\Rightarrow \frac{-1}{\sqrt{20152015}+\sqrt{20152016}}+\frac{1}{\sqrt{20152017}+\sqrt{20152016}}< 0$

$\Rightarrow \sqrt{20152015}+\sqrt{20152017}< 2\sqrt{20152016}$

Answer 3

Kanzaki Mizuki: ok mình sửa lại bài rồi đó bạn.