Ta có :
\(S=\left(\dfrac{1}{2^2}-1\right)\left(\dfrac{1}{3^2-1}\right)...\left(\dfrac{1}{2016^2-1}\right)\)
\(S=\left(\dfrac{1.3}{2^2}\right)\left(\dfrac{2.4}{3^2}\right)...\left(\dfrac{2015.2017}{2016^2}\right)\)
\(S=\dfrac{1.3.2.4....2015.2017}{2^2.3^2....2016^2}\)
\(S=\dfrac{1.2017}{2.2016}=\dfrac{2017}{4032}\)
⇒ S > -1/2