a) \(\dfrac{-4}{5}\)và \(\dfrac{8}{-10}\)
Ta có \(\dfrac{8}{-10}\)=\(\dfrac{-4}{5}\)
=>\(\dfrac{-4}{5}\)=\(\dfrac{8}{-10}\)
b) \(\dfrac{2}{3}\)và \(\dfrac{3}{4}\)
Ta có: \(\dfrac{2}{3}=\dfrac{8}{12}\);\(\dfrac{3}{4}=\dfrac{9}{12}\)
Mà \(\dfrac{8}{12}< \dfrac{9}{12}\)
=>\(\dfrac{2}{3}\)<\(\dfrac{3}{4}\)
a) \(\dfrac{-4}{5}và\dfrac{8}{-10}\)
Quy đồng: \(\dfrac{-4}{5}=\dfrac{-8}{10}\)
Ta có :\(\dfrac{-8}{10}=\dfrac{8}{-10}\)
⇒ \(\dfrac{-4}{5}=\dfrac{8}{-10}\)
b) \(\dfrac{2}{3}và\dfrac{3}{4}\)
Quy đồng: \(\dfrac{2}{3}=\dfrac{8}{12}\) ; \(\dfrac{3}{4}=\dfrac{9}{12}\)
Ta có: \(\dfrac{8}{12}< \dfrac{9}{12}\)
⇒ \(\dfrac{2}{3}< \dfrac{3}{4}\)