ta có:\(\dfrac{101^{120}+1}{101^{103}+1}>1;\dfrac{101^{103}+1}{101^{104}+1}< 1\) => N<1<M
vậy N<M
Ta có M=\(\frac{101^{120}+1}{101^{103}+1}>1\)
N=\(\frac{101^{103}+1}{101^{104}+1}< 1\)
=>\(\frac{101^{103}+1}{101^{104}+1}< 1< \frac{101^{120}+1}{101^{103}+1}\)
=>\(\frac{101^{103}+1}{101^{104}+1}< \frac{101^{120}+1}{101^{103}+1}\)
=> N < M
Vaayj N < M