Có: \(\left(-\frac{1}{3}\right)^{100}=\left(-\frac{1}{3}\right)^{50}.\left(-\frac{1}{3}\right)^{50}=\left(\frac{1}{9}\right)^{50}\)
Mặc khác: \(\left(-\frac{1}{9}\right)^{48}< \left(\frac{1}{9}\right)^{50}\)
Vậy: \(\left(-\frac{1}{3}\right)^{100}>\left(-\frac{1}{9}\right)^{48}\)
Cho \(A=\left(\frac{1}{2^2}-1\right)\left(\frac{1}{3^2}-1\right)\left(\frac{1}{4^2}-1\right)......\left(\frac{1}{100^2}-1\right)\)
Hãy so sánh A với 1/2
so sánh các số sau: a,\(0,5\sqrt{100}-\sqrt{\frac{4}{25}}và\left(\sqrt{1\frac{1}{9}-\sqrt{\frac{9}{16}}}\right):5\)
So sánh B và \(\frac{-1}{2}\)
Cho B = \(\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).....\left(\frac{1}{100^2}-1\right)\)
\(\left(\frac{1}{4}-1\right)\left(\frac{1}{9}-1\right)\left(\frac{1}{16}-1\right)...\left(\frac{1}{81}-1\right)\left(\frac{1}{100}-1\right)\)
Tính nhanh .
so sánh
a)\(\left(\frac{1}{2}\right)^{27}và\left(\frac{1}{3}\right)^{18}\) b)\(\frac{-53}{78}và\frac{-57}{87}\)
bài 1: tính
a) \(\left(\frac{3}{7}\right)^0=\frac{7}{9}:\left(\frac{2}{3}\right)^2-\left|-\frac{4}{5}\right|\)
b) \(\frac{10^3+2.5^3+5^3}{55}\)
bài 2: so sánh
\(^{3^{2009}}\) và \(9^{1005}\)
thanksss~~~
So sánh
\(\left(\frac{1}{2}\right)^{200};\left(\frac{1}{3}\right)^{200}\)
Tính và so sánh :
a) (2 .5)2 và 22 . 52
b) \(\left(\frac{1}{2}.\frac{3}{4}\right)^3\) và \(\left(\frac{1}{2}\right)^3.\left(\frac{3}{4}\right)^3\)
So sánh
\(a,\left(-5\right)^{30}\&\left(-3\right)^{50}\)
\(b,\left(\frac{1}{16}\right)^{10}\&\left(\frac{1}{2}\right)^{50}\)
