e: \(3=\sqrt9>\sqrt8=2\sqrt2\)
=>\(3+1>1+2\sqrt2\)
=>\(4>1+2\sqrt2\)
f: \(2\sqrt6=\sqrt{24}<\sqrt{25}\)
=>\(2\sqrt6-1<\sqrt{25}-1\)
=>\(2\sqrt6-1<5-1=4\)
g: \(\sqrt3-2=\sqrt3-\sqrt4<0<\sqrt{0,5}\)
h: \(-3\sqrt3=-\sqrt{3^2\cdot3}=-\sqrt{27};-2\sqrt7=-\sqrt{2^2\cdot7}=-\sqrt{28}\)
mà \(-\sqrt{27}>-\sqrt{28}\)
nên \(-3\sqrt3>-2\sqrt7\)
