\(\cos x=0\) ko la nghiem cua pt
\(\cos x\ne0\Rightarrow\tan^2x-\sqrt{3}.\tan x=\dfrac{1}{2\cos^2x}=\dfrac{1}{2}\left(1+\tan^2x\right)\)
\(\Leftrightarrow\dfrac{1}{2}\tan^2x-\sqrt{3}\tan x-\dfrac{1}{2}=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\tan x=2-\sqrt{3}\\\tan x=-2-\sqrt{3}\end{matrix}\right.\Leftrightarrow...\)