\(S=\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+...+\frac{2}{93.95}\)
\(S=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+...+\frac{1}{93}-\frac{1}{95}\)
\(S=\frac{1}{5}-\frac{1}{95}\)
\(S=\frac{18}{95}\)
Vậy \(S=\frac{18}{95}\)
Giải
\(S=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+...+\frac{1}{93}-\frac{1}{95}\)
\(=\frac{1}{5}-\frac{1}{95}\)
\(=\frac{18}{95}\)
Vậy S=\(\frac{18}{95}\)
may bn giai giup minh bai hinh luon voi
S=\(\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+............+\frac{2}{93.95}\)
S=\(\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}+........+\frac{1}{93.95}\)
S=\(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+............+\frac{1}{93}-\frac{1}{95}\)
S=\(\frac{1}{5}-\frac{1}{95}=\frac{18}{95}\)
S = \(\frac{2}{5.7}\)+ \(\frac{2}{7.9}\)+ \(\frac{2}{9.11}\)+ .........+ \(\frac{2}{93.95}\)
S = \(\frac{2}{5}\)- \(\frac{1}{7}\)+ \(\frac{1}{7}\)- \(\frac{2}{9}\)+ \(\frac{2}{9}\)- \(\frac{2}{11}\)+ ... + \(\frac{2}{93}\)- \(\frac{2}{95}\)
S= ( \(\frac{1}{5}\)- \(\frac{1}{95}\)) + (\(\frac{-1}{7}\)+ \(\frac{1}{7}\)) + ( \(\frac{-1}{9}\)+ \(\frac{1}{9}\)) +...+ (\(\frac{-1}{93}\)+ \(\frac{1}{93}\))
S = \(\frac{1}{5}\)- \(\frac{1}{95}\)+0+0+...+0
S = \(\frac{19}{95}\) - \(\frac{1}{95}\)
S = \(\frac{19-1}{95}\)
S = \(\frac{18}{95}\)
Chúc bn học tốt!