ta có :\(9=3^2\\ 2=2\\ 5=5\\ 11=11\\ \Rightarrow BCNN\left(9;2;5;11\right)=2.3^2.5.11=990\\ \dfrac{-7}{9}=\dfrac{-770}{990};\dfrac{3}{2}=\dfrac{1485}{990};\dfrac{-7}{5}=\dfrac{-1386}{990};\dfrac{-4}{-5}=\dfrac{4}{5}=\dfrac{792}{990};\dfrac{9}{11}=\dfrac{810}{990}\\ 0< \dfrac{-1368}{990}< \dfrac{-770}{990}< \dfrac{792}{990}< \dfrac{810}{990}< \dfrac{1485}{990}\\ \Rightarrow0< \dfrac{-7}{5}< \dfrac{-7}{9}< \dfrac{-4}{-5}< \dfrac{9}{11}< \dfrac{3}{2}\)