Bài 8: Rút gọn biểu thức chứa căn bậc hai
Các câu hỏi tương tự
cho bieu thuc p=(x+1)(x+√x)/√x-x-√x, voi x>0
a/ rut gon bieu thuc
b/ tim gia tri cua x de gia tri cua bieu thuc p bang 2
CHO 2 BIET THUC A= x- can x binh/x-1 va
B= x-4/x+2 can x binh
a. rut gon a va b
Cho A = (1 - 4/ √x + 1 +1/ x+1 ). x-2√x / x-1
Với x > 0 , x khác 4
a, rut gon A
b, Tìm x để A = 1/2
\(\dfrac{x+2}{x\sqrt{x}-1}+\dfrac{\sqrt{x}+1}{x+\sqrt{x}+1}-\dfrac{1}{\sqrt{x}-1}\)
a, rut gon A
b, tinh A voi \(4-2\sqrt{3}\)
Rut gon bt C=\(\dfrac{\sqrt{4x+4+\dfrac{1}{x}}}{\sqrt{x}.\left|2x^2-x-1\right|}\)
cho P=\(\left(\dfrac{3}{\sqrt{x}-1}+\dfrac{\sqrt{x}-3}{x-1}\right):\left(\dfrac{x+2}{x+\sqrt{x}-2}-\dfrac{\sqrt{x}}{\sqrt{x}+2}\right)\\ \)
a, rut gon
b, tim x de P=\(\sqrt{x}-1\)
B=\(\left(\frac{1}{x+\sqrt{x}}+\frac{1}{\sqrt{x}+1}-1\right):\frac{\sqrt{x}-1}{\sqrt{x}-2}\)
a,Rut gon B
b,Tim cac gia tri cua x de 3B=\(2\sqrt{x}-7\)
RUT GON:
\(\sqrt{2x+1-2\sqrt{\left(x-1\right)\left(x+2\right)}}\)
Bai tap: Cho:
\(A=\left(\dfrac{1}{x+\sqrt{x}}+\dfrac{1}{\sqrt{x}+1}\right):\dfrac{\sqrt{x}-1}{x+2\sqrt{x}+1}+1\)
a) Rut gon
b) Tinh gia tri cua A voi \(x=1\dfrac{1}{3}\)