Question

rút gọn (x+3)^2+(x-2)^2-2(x+3)(x-2)

Answer 1

help me

 

Answer 2

\(\left(x+3\right)^2+\left(x-2\right)^2-2\cdot\left(x+3\right)\left(x-2\right)\)\(=\left[\left(x+3\right)^2-2\cdot\left(x+3\right)\left(x-2\right)\right]+\left(x+2\right)^2\)\(=\left[x+3\cdot\left(x+3-2x+4\right)\right]+\left(x+2\right)^2\)

Tự làm tiếp.....

Answer 3

Ta có: \(\left(x+3\right)^2+\left(x-2\right)^2-2\left(x+3\right)\left(x-2\right)\)

\(=\left(x+3\right)^2-2\cdot\left(x+3\right)\cdot\left(x-2\right)+\left(x-2\right)^2\)

\(=\left(x+3-x+2\right)^2\)

\(=5^2=25\)