Đặt \(A=\sqrt[3]{54+30\sqrt{3}}+\sqrt[3]{54-30\sqrt{3}}\)
\(=\sqrt[3]{27+27\sqrt{3}+3\sqrt{3}+27}+\sqrt[3]{27-27\sqrt{3}-3\sqrt{3}+27}\)
\(=\sqrt[3]{\left(3+\sqrt{3}\right)^3}+\sqrt[3]{\left(3-\sqrt{3}\right)^3}\)
\(=3+\sqrt{3}+3-\sqrt{3}\)
\(=6\)
Vậy \(A=6\)