1)
\(a.\frac{30}{48}=\frac{30:6}{48:6}=\frac{5}{8}\)
\(b.\frac{-104}{182}=\frac{-104:2}{182:2}=\frac{-52}{91}\)
a, \(\frac{30}{48}\)= \(\frac{5}{8}\)
b, - \(\frac{104}{182}\)= \(\frac{-52}{91}\)
\(a)\) \(\frac{30}{48}=\frac{30:6}{48:6}=\frac{5}{8}\)
\(b) \) \(\frac{-104}{182}=\frac{-104:26}{182:26}=\frac{-4}{7}\)