A=\(\frac{2x+1}{x-3}+\frac{x-10}{x-3}\)=\(\frac{2x+1+x-10}{x-3}\)=\(\frac{3x-9}{x-3}=\frac{3\left(x-3\right)}{x-3}=3\)
B=\(\frac{3x}{x-2}-\frac{-24}{x-3}=\frac{3x}{x-2}+\frac{24}{x-3}\)=\(\frac{3x\left(x-3\right)}{\left(x-2\right)\left(x-3\right)}\)+\(\frac{24\left(x-2\right)}{\left(x-2\right)\left(x-3\right)}\)=\(\frac{3x^2-9x+24x-48}{\left(x-2\right)\left(x-3\right)}\)
=\(\frac{3x^2+15x-48}{\left(x-2\right)\left(x-3\right)}\)