Question

Rút gọn biểu thức:(2x-3)(2x+3)-(x+5)^2-(x-1)(x+2)

Answer 1

Ta có :

\(\left(2x-3\right)\left(2x+3\right)-\left(x+5\right)^2-\left(x-1\right)\left(x+2\right)\)

\(=4x^2-9-x^2-10x-25-x^2-x+2\)

\(=2x^2-11x-32\)

Answer 2

\(\left(2x-3\right)\left(2x+3\right)-\left(x+5\right)^2-\left(x-1\right)\left(x+2\right)\)

\(=4x^2-9-x^2-10x-25-x^2-x+2\)

\(=2x^2-11x-32\)

Answer 3

(2x - 3)(2x + 3) - (x + 5)² - (x - 1)(x + 2)

= 4x² - 9 - (x² + 10x + 25) - (x² + 2x - x - 2)

= 4x² - 9 - x² - 10x - 25 - x² - x + 2

= 2x² - 11x - 32

Answer 4

=[2x-3][2x+3]-[x+5]^2-[x-1][x+2]
=4x^2-9-[x^2+10x+25][-x^2+2x-x-2]
=4x^2-9-x^2-10x-25-x^2-x+2
=2x^2-11x-32