Question

Rút gọn biểu thức : 

\(B=2\left|x+1\right|-\left|x-1\right|\)

 

Answer 1

\(B=2\left|x+1\right|-\left|x-1\right|\)

- Nếu \(x\ge1\) thì : \(B=2.\left(x+1\right)-\left(x-1\right)=2x+2-x+1=x+3\)

- Nếu \(x=0\) thì :

\(B=2.\left(0+1\right)-\left(0-1\right)=2-\left(-1\right)=3\)

- Nếu \(x< 0\) thì :

\(B=2.\left(-x-1\right)-\left(-x+1\right)=-2x-2+x-1=-x-3\)